Python program from reversing a number, calculating number of digits

Write a program to reverse a number entered by the user. Call your program int_reverser.py. Suggested approach: 

a. Write an expression for the number of digits. This is the log in base 10 , math.log100, but it should be a whole number. 

b. Write a loop to keep dividing the number by 10 and printing the remainder. 

c. Add an accumulator variable for the result. Keep multiplying the result by 10 and adding the remainder. Example usage: 

Integer reverer 

Integer: 1234 

4321 

 
import math
n = int(input("Enter number: "))
numberOfDigit = math.log10(n)
if n<=10:
    result = n
else:
    result = 0
    i = 0
    while i<=numberOfDigit:
        result += n % 10
        result = result * 10
        n = n // 10
        i+=1
    result = result//10
 print(result)

Enter number: 1234
4321

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